| Ferdinand Rudolph Hassler - Arithmetic - 1826 - 232 pages
...given, to find the number of terms. When the first term is subtracted from the other term given, we have **the product of the common difference into the number of terms less one** as re J mainder; dividing this therefore by the common difference, we have the number of the term,... | |
| Jeremiah Day - Algebra - 1827 - 352 pages
...^=a^- (n— l)Xd; that is, 425. In an arithmetical progression, the last term is equal to the first, + **the product of the common difference into the number of terms less one.** Any other term may be found in the same way. For the series may be made to stop at any term, and that... | |
| Jeremiah Day - Algebra - 1831 - 356 pages
...z=a.\-(n — l) xd; that is, 425. In an arithmetical progression, the last term is equal to thefirst,-\- **the product of the common difference into the number of terms less one.** Any other term may be found in the same way. For the series may be made to stop at any term, and that... | |
| Charles Davies - Arithmetic - 1833 - 284 pages
...number of terms, and add the first term to the product. Hence we have CASE I. § 225. Having given **the first term, the common difference, and the number of terms, to find the last term.** RULE. Multiply the common difference by 1 less than the number of terms, and to the product add the... | |
| Francis Walkingame - 1833 - 204 pages
...tujind the less extreme. , RULE. Divide the sum by the number of terms : from the quotient subtract half **the product of the common difference into the number of terms less** 1 ; and the remainder will be the less extreme. (10) A man is to receive £360. at 12 several payments,... | |
| Mathematics - 1836 - 488 pages
...they form a descending series. In an arithmetical progression, the last term is equal to the first, + **the product of the common difference into the number of terms less one.** In an ascending series, the first term is the least, and the last the greatest. In a descending series,... | |
| Charles Davies - Arithmetic - 1838 - 292 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given **the first term, the common difference, and the number of terms, to find the last term.** RULE. Multiply the common difference by 1 less than the number of terms, and to the product add the... | |
| George Roberts Perkins - Arithmetic - 1841 - 274 pages
...number of terms is 48, and the sum of all the terms is 38496. What is the last term ? CASE XI. Given **the first term, the common difference, and the number of terms, to find the** sum of all the terms. RULE. To twice the first term, add the product of the common difference into... | |
| Charles DAVIES (LL.D.) - Arithmetic - 1843 - 348 pages
...than the number of terms, and add the first term to the product. Hence, we have CASE I. Having given **the first term, the common difference, and the number of terms, to find the last term.** RULE. Multiply the common difference by 1 less than the number of terms, and to the product add the... | |
| John Darby (teacher of mathematics.) - 1843 - 236 pages
...to exceed the former by 2d. What will her first payment be ? Ans. 3d. PROBLEM V. — Given the least **term, the common difference, and the number of terms to find the** greatest term. RULE. — Multiply the number of terms by the common difference, to this product add... | |
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