| William Crumpton - Arithmetic - 1766 - 342 pages
...ree. ______ _.. tilintal 'Parallelogram. RTILE. Multiply the bafe by the perpendicular altitude (viz. **the length by the breadth*) and the product will be the area or** fuperficial content. ' • i|t!.. 1 i . '. i EXAMPLE. Let the fide of a fquare be 3 feet 10 inches;... | |
| George Adams - Geometry - 1813 - 648 pages
...work. OF TIMBER MEASURE. PROBLEM 1. Tofnd the area, or superficial content in feet in a board or plank. **Multiply the length by the breadth, and the product will be the** content required. Note. If the board is tapering, add the breadth of the two ends together, and take... | |
| Nathan Daboll - Arithmetic - 1815 - 250 pages
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676-4-160=4"i 36r. the Answer. **ART. 2. To measure a parallelogram, or long square....product will be the area, or superficial content.** EXAMPLE8. 1. A certain garden, in form of a long square, is 96ft. ;ong, and 54 wide; how many square... | |
| Nathan Daboll - Arithmetic - 1817 - 252 pages
...Therefore, 26X26-=676 sq. rods, and 676-*-160=4a. S6r. the ' ART. 2. To measure a parallelogram, or lofig **square. RULE. Multiply the length by the breadth,...content. EXAMPLES. 1. A certain garden, in form of** a long square, is 96 ft. long, and 54 wide; how many square feet of ground ar» contained in it ? 4ns.... | |
| Nathan Daboll - Arithmetic - 1818 - 248 pages
...— 160 square rods make an acre. Therefore, 26x26=676 sq. rods, and 676-7-160=4*. 36r. the Answer. **ART. 2. To measure a Parallelogram, or long square. RULE. Multiply the length** bv the breadth, and the product will be the area or superficial content. •» EXAMPLES. .. 1. A certain... | |
| Nathan Daboll - Arithmetic - 1820 - 256 pages
...160 square rods make an acre. Therefore, 26x26=676 Sq. rods, and 6r6-=-160==4i«. 36r. the Answer. **ART. 2. To measure a parallelogram, or long square....content. EXAMPLES. 1. A certain garden, in form of** a long square, is 96 ft. long, and 54 wide; how many square feet of ground are contained in it ? Aris.... | |
| Matthew Iley - 1820 - 512 pages
...we have for the area 11924-6 on A, against 109-2 on B. PROBLEM II. To find the Area of a Rectangle. **RULE. Multiply the length by the breadth, and the product will be the area.** Let ABCD be a rectangle whereof the length is G3 inches, and the breadth 42 inches ; the area is required.... | |
| Nicolas Pike - Arithmetic - 1822 - 536 pages
...numbers, to the length , that distance, laid the same way from the breadth, will point out the answer. **ART. 2. To measure a Parallelogram or long Square....product will be the area, or superficial content.*** Let ABCD represent a parallelogram, whose A length is 5 feet, and breadth, 4 feet. Multiply 5 by 4.... | |
| Beriah Stevens - Arithmetic - 1822 - 436 pages
...four angles, the opposiles whereof are equal ; to find tbe superficial content thereof this is the **rule : — Multiply 'the length by the breadth, and the product will be the** superficial content or area. EXAMPLE. Let ABCD represent a parallelogram, whose length is 18, and breadth... | |
| Nathan Daboll - Arithmetic - 1824 - 264 pages
...make an acre. Therefore, 26x26=676 sq. rods, and 676-M60=4«. * 36r. the Answer. ART. 2. To measure a **a parallelogram, or long square. RULE. Multiply the...content. EXAMPLES. 1. A certain garden, in form of** a long square, is 96 ft. ,ong, and 54 wide; how many square feet of ground are contained in it ? Jlns.... | |
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