| Peter Nicholson - 1809 - 426 pages
...189 343) 1200 1029 17100 PROBLEM V. To find the area of a trapezium. Multiply the diagonal by half **the sum of the two perpendiculars, falling upon it from the opposite angles, and** the product will be the area. EXAMPLE I. What is the area of a trapezium ABCD, the diagonal AC being... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...areaffa trapezium. RULE. Multiply the sum of the two perpendiculars by the diagonal upon which they fall, **from the opposite angles, and half the product will be the area.** Or, divide the trapezium into two triangles, in the most convenient manner ; and the sum of their areas... | |
| Peter Nicholson - Mathematics - 1825 - 1046 pages
...18 the 18 144 18 324 17100 Prob. 5. To find the area of a trapezium. Multiply the diagonal by half **the sum of the two perpendiculars-, falling upon it from the opposite angles, and** the product will be the area. Ex. What is the area of a trapezium ABCD, the diagonal AC being 36 feet,... | |
| Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...sides~1440 400 2)576000 Double area. 2.88000 4 3.52000 40 20.80000 • Ans. ZA. 3n. 20p. PROBLEM 4. , .. **To find the Area of a Trapezium. RULE. Multiply the diagonal by the sum of the two perpendiculars,** let fall upon it, from its opposite angles ; and half the product will be the area. EXAMPLE. Required... | |
| John Bonnycastle - Geometry - 1829 - 256 pages
...the other side ; required the breadth of the street. Ans. 76. 1233 feet . OF SUPERFICIES. PROBLEM V. **To find the area of a trapezium. RULE.* Multiply the...and half the product will be the area. EXAMPLES. 1.** Required the area of the trapezium BAED, whose diagonal BE is 84, the perpendicular AC 21, and DF 28.... | |
| Thomas Curtis - Aeronautics - 1829 - 810 pages
...separately, and their sum will be the area of the trapezium ; or multiply the diagonal by half the sum of the **perpendiculars falling upon it from the opposite angles, and half the product will be the area.** Example. — What is the area of a trapezium whose diagonal is 80-5, and perpendiculars 24-5, and 30-1... | |
| John Bonnycastle - Measurement - 1833 - 310 pages
...window, 36 feet high, on the other side ; required the breadth of the street. Ans. 76.1233/eei PROBLEM V. **To find the area of a trapezium. RULE.* Multiply the diagonal by the sum of the two** perpendicu lars falling upon it from the opposite angles, and half the product will be the area. EXAMPLES.... | |
| Charles Haynes Haswell - Engineering - 1844 - 298 pages
...TRAPEZIUMS AND TRAPEZOIDS. To find the Area of a Trapezium — fig. 8. RULE. — Multiply the diagonal ac **by the sum of the two perpendiculars falling upon...opposite angles, and half the product will be the area.** To find the Area of a, Trapezoid — fig. 9. RULE. — Multiply the sum of the parallel sides a 4,... | |
| John Bonnycastle - Geometry - 1848 - 312 pages
...window, 36 feet high, on the other side ; required the breadth of the^treet. Ans. 76.1233/eet PROBLEM V. **To find the area of a trapezium. RULE.* Multiply the diagonal by the sum of the two** perpendicu lars falling upon it from the opposite angles, and half the product will be the area. ,... | |
| John Bonnycastle - Geometry - 1848 - 320 pages
...To find the area of a trape2ium, RULE.* Multiply the diagonal by the sum of the two perpendieu lars **falling upon it from the opposite angles, and half the product will be the area. EXAMPLES. 1.** Required the area of the trapezium BAED, whose diagonal BE is 84, the perpendicular AC 21, and DF 28.... | |
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