 | Nathan Daboll - Arithmetic - 1829 - 254 pages
...dividend. 3. Place the double of the root, already found, on the ^teft hand of the dividend, for a divisor. 4. Place such a figure at the right hand...also the same figure in the root, as when multiplied mto the whole (increased divisor) the product shall be ftqual to, or the next less th:m the dividend,... | |
 | William Kinne - 1829 - 248 pages
...subtract it therefrom, and to the remainder bring down the next period for : dividend. 3. Place the double of the root already found on the left hand of the dividend for a divisor. 4. Consider what figure must be annexed to the divisor, so that if the result be multiplied... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...the left of the dividend for a divisor. -\ IV. Write such a figure at the right hand of the Mvisor, also the same figure in the root, as, when multiplied into the divisor thus increased, the product shall be eqva\ to, or nеfi less than the dividend. This quotient... | |
 | Daniel Adams - Arithmetic - 1830 - 232 pages
...subtract it therefrom, and to the remainder t.ring down the next period for a dividend. 3. " Place the double of the root, already found, on the left hand of the d-vidend for a divisor. 4. " Seek how often the divisor is contained in the dividend, (except the right... | |
 | Lyman Cobb - Arithmetic - 1832 - 228 pages
...'.he remainder bring down the two figures of the next foilowin f period for a dividend. 3. Plac.e the double of the root, already found, on the left hand of the dividend for a divisor. Seek how often the divisor is contained in the dividend, (excepting the right hand figure,)... | |
 | George Alfred - Arithmetic - 1834 - 336 pages
...the remainder annex the next period in the given number to form a resolvend or dividual. 4. Place the double of the root, already found, on the left hand of the resolvend, fora divisor. 5. Seek how often the said divisor is contained in the resolvend, (omitting... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...sides. Then 20+20=40, the length of the whole addition. To find the width of the addition, we place the double of the root already found, on the left hand of the dividend, for a divisor. If we divide 176, the number of rods to be added, by 40, . . the length of the addition,... | |
 | Nathan Daboll - Arithmetic - 1837 - 262 pages
...subtract it therefrom, and to the remainder bring down the next period, for a dividend. 3. Place the double of the root, already found, on the left hand of the dividend for a olvispr. 4. Place such a figure at the right hand of the divisor, and also the same figure in... | |
 | Nathan Daboll - 1839 - 220 pages
...for a dividend. 3. Double the root already found, and place it at the left hand of the dividend for a divisor. 4. Place such a figure at the right hand...same figure in the root, as, when multiplied into the divisor thus increased, the product shall be equal to, or next less than the dividend ; this will be... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 352 pages
...subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend (except the right hand figure)... | |
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